33x^2-50x-16=0

Solution for 33x^2-50x-16=0 equation:

33x^2-50x-16=0

a = 33; b = -50; c = -16;
Δ = b2-4ac
Δ = -502-4·33·(-16)
Δ = 4612
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4612}=\sqrt{4*1153}=\sqrt{4}*\sqrt{1153}=2\sqrt{1153}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{1153}}{2*33}=\frac{50-2\sqrt{1153}}{66}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{1153}}{2*33}=\frac{50+2\sqrt{1153}}{66}
$